# Water is flowing

Given,

Diameter of the cylindrical pipe = 2 cm
Radius of the cylindrical pipe = 1 m
Height of the cylindrical pipe = 0.4m/s = 40 cm/s

Water flown in 1 sec = 40 cm
Water flown in 30 minutes (30 × 60 seconds)
= 40 × 60 × 30 m = 72000 cm

Radius of cylindrical tank = 40 cm
Let Height be h,
As we can see the volume of water which passes through the cylindrical pipe is equal to the volume of water present in the cylindrical tank after half an hour.
So,

Volume of water which passes through the cylindrical = volume of water present in the cylindrical tank after half an hour
πr2h = πr2h
(1)2 × 72000 = (40)2 × h
72000 = 1600 × h
h = 45 cm

Hence,

The rise in level of water in tank in half an hour will be 45 cm.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation view all courses 