# A spherical shell

External diameter of shell = 24cm and

Internal diameter of shell = 18cm

So,

External radius of shell = 12 cm and

Volume of lead in the shell = π[123–93]cm3

Let the radius of the cylinder be r cm

Height of the cylinder = 37 cm

Volume of the cylinder = πr2h = πr2(37)

π[123–93] = πr2 × 37

π × 999 = πr2 × 37

r2 = × π × 999 × π = 36cm2

r = = 6cm

Hence, diameter of the base of the cylinder = 12 cm

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