# The Sum of the ra

Let the Radius of the solid cylinder be ‘r’ m and its height be ‘h’ m.

Given,

Sum of radius and height of solid cylinder = 37 m

r + h = 37 m

r = 37 – h

Total surface area of solid cylinder = 1628 m2

Total surface area of solid cylinder is given by 2πr (h + r)

2πr (h + r) =1628 m2

Substituting the value of r + h in the above equation

2πr × 37 = 1628 m2

r = 1628 × 7/22 × 1/2 × 1/37 m

r = 7 m

Since, r + h = 37 m

h = 37 – r m

h = 37 – 7 m = 30 m

Volume of solid cylinder = πr2h

= 22/7 × 72 × 30 m2

= 4620 m2

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Trigo Marathon Part 245 mins
Trigo Marathon Part 146 mins
Application of Trigo Important Questions44 mins
Chemical Properties of Metal and Non Metal61 mins
Arithmetic Progression and 'nth' Term of AP55 mins
Extraction of Metal56 mins
Purification of Metals60 mins
Introduction of Metal and Non Metal59 mins
Properties of Metal and Non Metal59 mins
Heights and Distances - I54 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses