# A cubical block o

Length of side of cubical block = a = 10 cm

Since, a cubical block is surmounted by a hemisphere, so, the largest diameter of hemisphere = 10 cm

Since, hemisphere will be touching the sides of cubical block.

Radius of hemisphere = r = Diameter ÷ 2 = 10/2 cm = 5 cm

Surface area of solid = Surface area of cube – Area of circular part of hemisphere + Curved surface area of hemisphere

Total Surface area of solid = 6a2 – πr2 + 2πr2 = 6a2 + πr2

= 6 × 10 × 10 cm2 + 3.14 × 5 × 5 cm2

= 678.5 cm2

Rate of painting = Rs 5/100 cm2

Cost of painting the total surface area of the solid so formed = Total Surface area of solid × Rate of painting

Cost of painting the total surface area of the solid = Rs 5/100 × 678.5

= Rs 33.925

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Trigo Marathon Part 245 mins
Trigo Marathon Part 146 mins
Application of Trigo Important Questions44 mins
Chemical Properties of Metal and Non Metal61 mins
Arithmetic Progression and 'nth' Term of AP55 mins
Purification of Metals60 mins
Extraction of Metal56 mins
Introduction of Metal and Non Metal59 mins
Properties of Metal and Non Metal59 mins
Heights and Distances - I54 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses