Q. 244.8( 9 Votes )

Answer :

Height of solid cylinder = h = 14 cm

Diameter of solid cylinder = 7 cm

Radius of solid cylinder = r = Diameter ÷ 2 = 7/2 cm = 3.5 cm

Volume of solid cylinder = πr^{2}h

= 22/7 × 3.5 × 3.5 × 14 cm^{3}

= 539 cm^{3}

Height of conical cavity = h’ = 4 cm

Radius conical cavity = r’ = 2.1 cm

Volume of conical cavity = 1/3 πr’^{2}h’

= 1/3 × 22/7 × 2.1 × 2.1 × 4 cm^{3}

= 18.48 cm^{3}

Since, there are two conical cavities

∴ Volume of two conical cavities = 2 × 18.48 cm^{3} = 36.96 cm^{3}

Volume of remaining solid = Volume of solid cylinder – Volume of two conical cavity

Volume of remaining solid = 539 cm^{3} – 36.96 cm^{3}

= 502.04 cm^{3}

Rate this question :

How useful is this solution?

We strive to provide quality solutions. Please rate us to serve you better.

PREVIOUSFrom a solid cylinder of height 2.8 cm and diameter 4.2 cm, a conical cavity of the same height and same diameter is hollowed out. Find the total surface area of the remaining solid.NEXTA metallic cylinder has radius 3 cm and height 5 cm. To redue its weight, a conical hole is drilled in the cylinder. The conical hole has a radius of 3/2 cm and its depth is 8/9 cm. Calculate the ratio of the volume of metal left in the cylinder to the volume of metal taken out in conical shape.