Answer :

A solid is in the form of a right circular cone mounted on a hemisphere.


Let r be the radius of hemisphere and cone


Let h be the height of the cone


Radius of hemisphere = r = 2.1 cm


Volume of hemisphere = 2/3 πr3


= 2/3 × 22/7 × 2.1 × 2.1 × 2.1 cm3


= 19.404 cm3


Height of cone = h = 4 cm


Radius of cone = r = 2.1 cm


Volume of cone = 1/3 πr2h


= 1/3 × 22/7 × 2.1 × 2.1 × 4 cm3


= 18.48 cm3


Volume of solid = Volume of hemisphere + Volume of cone


= 19.404 cm3 + 18.48 cm3 = 37.884 cm3


The solid is placed in a cylindrical tub full of water in such a way that the whole solid is submerged in water, so, to find the volume of water left in the tub we need to subtract volume of solid from cylindrical tub.


Radius of cylinder = r’ = 5 cm


Height of cylinder = h’ = 9.8 cm


Volume of cylindrical tub = πr’2h’ = 22/7 × 5 × 5 × 9.8 cm3


= 770 cm3


Volume of water left in the tub = Volume of cylindrical tub – Volume of solid


Volume of water left in the tub = 770 cm3 – 37.884 cm3 = 732.116 cm3


Volume of water left in the tub is 732.116 cm3


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