# A cylindrical con

Radius of cylindrical container = r = 6 cm

Height of cylindrical container = h = 15 cm

Volume of cylindrical container = πr2h

= 22/7 × 6 × 6 × 15 cm3

= 1697.14 cm3

Whole ice-cream has to be distributed to 10 children in equal cones with hemispherical tops.

Let the radius of hemisphere and base of cone be r’

Height of cone = h = 4 times the radius of its base

h’ = 4r’

Volume of Hemisphere = 2/3 π(r’)3

Volume of cone = 1/3 π(r’)2h’ = 1/3 π(r’)2 × 4r’

= 2/3 π(r’)3

Volume of ice-cream = Volume of Hemisphere + Volume of cone

= 2/3 π(r’)3 + 4/3 π(r’)3 = 6/3 π(r’)3

Number of ice-creams = 10

total volume of ice-cream = 10 × Volume of ice-cream

= 10 × 6/3 π(r’)3 = 60/3 π(r’)3

Also, total volume of ice-cream = Volume of cylindrical container

60/3 π(r’)3 = 1697.14 cm3

60/3 × 22/7 × (r’)3 = 1697.14 cm3

(r’)3 = 1697.14 × 3/60 × 7/22 = 27 cm3

r = 3 cm

Radius of ice-cream cone = 3 cm

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