Q. 14

# A toy is in the f

Answer :

The toy is in the form of a cone mounted on a hemisphere.

Total height of toy = h = 31 cm

Radius of toy = r = 7 cm

Surface area of hemispherical part toy = 2πr2

= 2 × 22/7 × 72 cm2

= 308 cm2

Height of conical part of toy = hcone = Total height of toy – Radius of toy

Height of conical part of toy = hcone = 31 – 7 = 24 cm

Let the slant height of the conical part be l

l2 = hcone2 + r2

l2 = 242 + 72 = 576 + 49 cm2 = 625 cm2

l = 25 cm

Surface area of conical part of toy = πrl

= 22/7 × 7 × 25 cm2

= 550 cm2

Total surface area of toy = Surface area of hemispherical part of toy + Surface area of conical part of toy

Total Surface area of toy = 308 cm2 + 550 cm2 = 858 cm2

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos  Trigo Marathon Part 245 mins  Trigo Marathon Part 146 mins  Application of Trigo Important Questions44 mins  Arithmetic Progression and 'nth' Term of AP55 mins  Chemical Properties of Metal and Non Metal61 mins  Purification of Metals60 mins  Extraction of Metal56 mins  Introduction of Metal and Non Metal59 mins  Properties of Metal and Non Metal59 mins  Heights and Distances - I54 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation view all courses 