Answer :

Rearranging the terms we get:



Integrating both the sides we get:



log|1 + sinx| = - log|1 + cosy| + logc


log|1 + sinx| + log|1 + cosy| = logc


(1 + sinx)(1 + cosy) = c


Ans: (1 + sinx)(1 + cosy) = c


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