Q. 674.3( 6 Votes )

# Evaluate the following integrals:

Answer :

We can write x^{2} + 2x + 1 + 1 = (x + 1)^{2} + 1

⇒

Assume x + 1 = tant

⇒ dx = sec^{2}t.dx

⇒

⇒ tan^{2}t + 1 = sec^{2}t.

⇒

⇒

⇒ log|sint| + c

⇒

But tant = x + 1

⇒

The final answer is

⇒

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