# Evaluate the following integrals:∫ 2x sec3 (x2 + 3) tan (x2 + 3) dx

sec3 (x2 + 3) can be written as sec2 (x2 + 3). sec (x2 + 3)

Now the question becomes

Assume sec (x2 + 3) = t

d(sec (x2 + 3)) = dt

2x sec (x2 + 3) tan (x2 + 3)dx = dt

Substituting t and dt in the given equation

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