# Evaluate the foll

Assume log(secx + tanx) = t

d(log(secx + tanx)) = dt

(use chain rule to differentiate first differentiate log(secx + tanx) then (secx + tanx)

= dt

secx dx = dt

Put t and dt in given equation we get

Substituting the values oft and dt we get

But t = log(secx + tanx)

.

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