Q. 203.6( 5 Votes )

Evaluate the following integrals:


Answer :

Assume x2 + 1 = t


d(x2 + 1) = dt


2x dx = dt



x3 can be write as x2.x


Now the given equation becomes



x2 + 1 = t x2 = t - 1






But t = (x2 + 1)





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