Q. 135.0( 4 Votes )

Evaluate the following integrals:


Answer :

In this equation, we can manipulate numerator


Cos3x = cos2x.cosx


Now the equation becomes,



Cos2x = 1 - sin2x



Now,


Let us assume sinx = t


d(sinx) = dt


cosx dx = dt


Substitute values of t and dt in the above equation






But t = sinx


.


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