Q. 19

# Evaluate the foll

Assume acos2x + bsin2x = t

d(acos2x + bsin2x) = dt

( - 2acosx.sinx + 2bsinx.cosx)dx = dt

(bsin2x - asin2x)dx=dt

(b - a)sin2xdx=dt

Sin2xdx =

Put t and dt in given equation we get

= ln|t| + c.

But t = acos2x + bsin2x

= ln| acos2x + bsin2x | + c.

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