Q. 535.0( 2 Votes )

Evaluate the foll

Answer :


Let, x2=y



1=A(y + 2) + B(y + 1)


1=(A + B)y + 2A + B


On equating similar terms, we get,


A + B=0, and 2A + B=1


We get, A=1, B= – 1





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