Q. 355.0( 3 Votes )

# Evaluate the following integral:

18 = A(x2 + 4) + (Bx + C)(x + 2)

Equating constants

18 = 4A + 2C

Equating coefficients of x

0 = 2B + C

Equating coefficients of x2

0 = A + B

Solving, we get

Thus,

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