Q. 274.1( 8 Votes )

Evaluate the foll

Answer :



3x – 2 = A(x + 1)(x + 3) + B(x + 3) + C(x + 1)2


Put x = – 1


– 3 – 2 = A × 0 + B × ( – 1 + 3) + C × 0


– 5 = 2B



Put x = – 3


– 9 – 2 = C × ( – 2)( – 2)


– 11 = 4C



Equating coefficients of constants


– 2 = 3A + 3B + C




Thus,




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