# In the given figure, AB||DC and DA AB If cm, cm, cm and CL AB the area of trap. ABCD isA. 84 cm2B. 72 cm2C. 80 cm2D. 91 cm2

Given:

AB||DC, DA AB and CL AB

cm

cm

cm

Therefore here AL = DC

That is AL = 7 cm

Hence LB = AB – AL = 13 – 7 = 6cm

In LCB using Pythagoras theorem

BC2 = BL2 + CL2

102 = 62 + CL2

100 = 36 + CL2

CL2 = 100 – 36

CL2 = 64

CL = 8

Here CL = AD = height of the trapezium

Therefore height = 8 cm

Now,

We know that area of trapezium is × (sum of parallel sides) × height

Therefore Area of trapezium = × (7 +13) × 8 = 80 cm2.

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