In the given figu

Given:

AB||DC, DA AB and CL AB

cm

cm

cm

Therefore here AL = DC

That is AL = 7 cm

Hence LB = AB – AL = 13 – 7 = 6cm

In LCB using Pythagoras theorem

BC² = BL² + CL²

10² = 6² + CL²

100 = 36 + CL²

CL² = 100 – 36

CL² = 64

CL = 8

Here CL = AD = height of the trapezium

Therefore height = 8 cm

Now,

We know that area of trapezium is × (sum of parallel sides) × height

Therefore Area of trapezium = × (7 +13) × 8 = 80 cm².