Q. 64.6( 23 Votes )

# The area of a tra

Answer :

Given

Lengths of the parallel sides are in the ratio 4:5

Therefore let one of the side length be 4X and other side length be 5X

Area of trapezium= 405 cm^{2}

Let Height (h) =18 cm

We know that area of trapezium is × (sum of parallel sides) × height

Therefore Area of trapezium is x (4X +5X) × 18 =405 cm^{2}.

× (4X + 5X) × 18 =405

⇒(9X) × 9 =405

⇒ 81X = 405

⇒ X = = 5

.^{.}. Length of the parallel sides is 4X=4 × 5 =20 cm and 5X = 5 × 5 = 25 cm.

Therefore lengths of the parallel sides are 20 cm, 25 cm.

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