Q. 484.5( 4 Votes )

# In the given figu

Answer :

Given:

OP = 21 m = r_{1}

OR = 14 m = r_{2}

Let the quadrants made by outer and inner circles be Q_{1} and Q_{2,} with radius r_{1} and r_{2} respectively.

Then, Area of flower bed = Area of Q_{1} – Area of Q_{2}

∵ Area of Quadrant = πr^{2}

∴ Area of Q_{1} = πr_{1}^{2}

= × × 21 × 21

= m^{2}

Similarly, Area of Q_{2} = πr_{2}^{2}

= × × 14 × 14

= m^{2}

Thus, Area of flower bed = -

= = 192.5 m^{2}

__Hence, the area of the flower bed is 192.5 m ^{2}.__

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