Q. 93.8( 4 Votes )

Given the sum of

Answer :

Let us say the sum of perimeter of square and circumference of circle be L


Given: Sum of the perimeters of a square and a circle.


Assuming, side of square = a and radius of circle = r


Then, L = 4a + 2πr …1


Let the sum of area of square and circle be S


So, S = a2 + πr2


S =


Condition for maxima and minima



= 0







So, for >0


This is the condition for minima


From equation 1



Substituting from equation 2





a = 2r


Hence, proved.


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