Q. 7

A wire of length

Let the length of side of square be a and radius of circle be r.

It is given that wire is cut into two parts to form a square and a circle

Therefore, perimeter of square + circumference of circle = length of wire

4a + 2πr = 28

a = …1

Let us assume area of square + area of circle = S

S = a2 + πr2

S = + πr2 (from equation 1)

Condition for maxima and minima

…2

So, for >0

This is the condition for minima

From equation 1

a =

Substituting from equation 2

a =

a =

a =

Hence, radius of circle and length of square be and respectively.

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