How many cubic ce

Given,

External dimensions of box = 36cm×25cm×16.5cm

Thickness of iron = 1.5 cm

Inner dimensions of box = [(36-3)×(25-3)×(16.5-1.5)]

=33cm×22cm×15cm

Volume of iron used = external volume – internal volume

= 36×25×16.5 – 33×22×15 = 3960 cm³

∵ weight of 1 cm³ iron = 15 gm (given)

∴ weight of 3960 cm³ iron = 3960×15 = 59400 gm = 59.4 kg