Q. 74.0( 35 Votes )
Construct a parallelogram ABCD, in which diagonal AC=3.8cm, diagonal BD=4.6cm and the angle between AC and BC is 60°.
STEP 1: At first draw the diagonal AC of 3.8 cm.
STEP 2: Now from the centre of AC (let M), draw a perpendicular line.
STEP 3: From C draw a 600 angle downward with the help of protractor. The intersection point between the line and the perpendicular is B.
STEP 4: From B draw an arc of radius 4.6 cm on the perpendicular line. The intersecting point is D. Join AD, CD and AB.
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