Q. 243.8( 4 Votes )

# In the given figu

Given:

BD = 24 cm

AL = 9 cm

CM = 12 cm

Area of ∆ADB = 1/2 × BD × AL

= 1/2 × 24 cm × 9 cm

= 108 cm2

In ∆CDB,

Area of ∆CDB = 1/2 × BD × CM

= 1/2 × 24 cm × 12 cm

= 144 cm2

Now,

Area of quadrilateral ABCD = Area of ∆ADB + Area of ∆ADB

= 108 cm2 + 144 cm2

= 252 cm2

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