Q. 243.8( 4 Votes )

In the given figure, ABCD is a quadrilateral in which diagonal BD = 24 cm, AL BD and CM BD such that AL = 9 cm and CM = 12 cm. Calculate the area of the quadrilateral.


Answer :

Given:


BD = 24 cm


AL = 9 cm


CM = 12 cm


In ∆ADB,


Area of ∆ADB = 1/2 × BD × AL


= 1/2 × 24 cm × 9 cm


= 108 cm2


In ∆CDB,


Area of ∆CDB = 1/2 × BD × CM


= 1/2 × 24 cm × 12 cm


= 144 cm2


Now,


Area of quadrilateral ABCD = Area of ∆ADB + Area of ∆ADB


= 108 cm2 + 144 cm2


= 252 cm2


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.