Q. 173.8( 8 Votes )

# The dimensions of a room are 14 m x 10 m x 6.5 m. There are two doors and 4 windows in the room. Each door measures 2.5 m x 1.2 m and each window measures 1.5 m x 1m. Find the cost of painting the four walls of the room at RS. 35 per m^{2}.

Answer :

Given:

Length of walls = 14 m

Breadth of walls = 10 m

Height of walls = 6.5 m

Length of windows = 1.5 m

Breadth of windows = 1 m

Length of doors = 2.5 m

Breadth of doors = 1.2 m

Cost = Rs 35 per m^{2}

Now,

Area of four walls = 2(Length of walls × Height of walls) + 2(Breadth of walls × Height of walls)

= 2(14 × 6.5) + 2(10 × 6.5)

= 182 m^{2} + 130 m^{2}

= 312 m^{2}

Area of two doors = 2(Length of doors × Breadth of doors)

= 2(2.5 × 1.2)

= 6 m^{2}

Area of four windows = 4(Length of windows × Breadth of windows)

= 4(1.5 × 1)

= 6 m^{2}

Therefore,

Area to be painted = Area of 4 walls–(Area of 2 doors + Area of 4 windows)

= 312 m^{2} – (6 m^{2} + 6 m^{2})

= 300 m^{2}

Cost of painting = 300 m^{2} × Rs 35 per m^{2}

= Rs 10500

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