Q. 173.8( 8 Votes )

The dimensions of a room are 14 m x 10 m x 6.5 m. There are two doors and 4 windows in the room. Each door measures 2.5 m x 1.2 m and each window measures 1.5 m x 1m. Find the cost of painting the four walls of the room at RS. 35 per m2.

Answer :

Given:


Length of walls = 14 m


Breadth of walls = 10 m


Height of walls = 6.5 m


Length of windows = 1.5 m


Breadth of windows = 1 m


Length of doors = 2.5 m


Breadth of doors = 1.2 m


Cost = Rs 35 per m2


Now,


Area of four walls = 2(Length of walls × Height of walls) + 2(Breadth of walls × Height of walls)


= 2(14 × 6.5) + 2(10 × 6.5)


= 182 m2 + 130 m2


= 312 m2


Area of two doors = 2(Length of doors × Breadth of doors)


= 2(2.5 × 1.2)


= 6 m2


Area of four windows = 4(Length of windows × Breadth of windows)


= 4(1.5 × 1)


= 6 m2


Therefore,


Area to be painted = Area of 4 walls–(Area of 2 doors + Area of 4 windows)


= 312 m2 – (6 m2 + 6 m2)


= 300 m2


Cost of painting = 300 m2 × Rs 35 per m2


= Rs 10500


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