Answer :

Given :


AB = 2.9 cm , AC = 3.2 cm , CD = 2.7 cm , DA = 3.4 cm ,


Construction :


Step 1 : Draw segment AB of length 2.9 cm.



Step 2 : Draw angle A of 70 degrees.



Step 3 : Taking A as centre draw an arc of radius 3.4 cm, which cuts the segment BP. Point of intersection is D.



Step 4 : Taking A as centre draw an arc of radius 3.2 cm.



Step 5 : Taking D as centre draw arc of radius 2.7 cm, which cuts the arc drawn in step 4. Point of intersection is C.



Step 6 : Join CD, AC and BC.



ABCD is the required quadrilateral.

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