# Construct a quadrilateral ABCD in which AB=2.9cm, BD=3.2cm, CD=2.7cm, DA=3.4cm and ∠A = 70°.

Given :

AB = 2.9 cm , AC = 3.2 cm , CD = 2.7 cm , DA = 3.4 cm ,

Construction :

Step 1 : Draw segment AB of length 2.9 cm.

Step 2 : Draw angle A of 70 degrees.

Step 3 : Taking A as centre draw an arc of radius 3.4 cm, which cuts the segment BP. Point of intersection is D.

Step 4 : Taking A as centre draw an arc of radius 3.2 cm.

Step 5 : Taking D as centre draw arc of radius 2.7 cm, which cuts the arc drawn in step 4. Point of intersection is C.

Step 6 : Join CD, AC and BC.

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