Q. 74.3( 24 Votes )

Construct a quadrilateral ABCD in which AB=BD=3.5cm, AD=CD=5.2 and ∠ABC=120o

Answer :

Given :


AB = BD = 3.5 cm , AD = CD = 5.2 cm ,


Construction :


Step 1 : Draw segment AB of length 3.5 cm.



Step 2 : Taking A as centre draw an arc of radius 5.2 cm.



Step 3 : Taking B as centre draw an arc of radius 3.5 cm, which cuts the arc drawn in step 2. Point of intersection of two arcs is D.



Step 4 : Join AD and BD.



Step 5 : Draw angle ABC of 120 degrees.



Step 6 : Taking B as centre draw an arc of radius 5.2 cm, which cuts the segment BP. Point of intersection is C.



Step 7 : Join CD



ABCD is the required quadrilateral.

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