Q. 34.1( 34 Votes )

# Construct a quadrilateral ABCD in which AB=3.5cm, BC=3.58cm, CD=DA=4.5 cm and diagonal BD=5.6cm.

Given :

AB = 3.5 cm , BC = 3.58 cm , CD = DA = 4.5 cm , BD = 5.6 cm.

Construction :

Step 1 : Draw segment AB of length 3.5 cm.

Step 2 : Taking A as centre draw an arc of radius 4.5 cm.

Step 3 : Taking B as centre draw an arc of radius 5.6 cm, which cuts the arc drawn in step 2. Point of intersection of two arcs is D.

Step 4 : Join AD and BD.

Step 5 : Taking B as centre draw an arc of radius 3.58 cm.

Step 6 : Taking D as centre draw arc of radius 4.5 cm, which cuts the arc drawn in step 5. Point of intersection of two arcs is C.

Step 7 : Join BC and CD.

ABCD is the required quadrilateral.

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