# Construct a quadrilateral ABCD in which AB=5.6cm, BC=4cm, ∠A= 50°, ∠B = 105° and ∠D = 80°.

Sum of all the angles of a quadrilateral is 360°.

∠A + ∠B + ∠C + ∠D = 360°
50° + 105° + ∠C + 80° = 360°
235° + ∠C = 360°
∠C = 360° - 235°
∠C = 125°

Construction:
1) Draw a line AB = 5.6 cm

2) At point A, Draw an ∠XAB = 50° with the help of a protector.

3) At point B, Draw an ∠YBA = 105° with the help of a protector.

4) With B as center, draw an arc of 4 cm which intersects the BY at C.

5) At point C, Draw ∠BCD = 125° such that D is a point on line AX.

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