# Construct a quadrilateral ABCD in which AB= 4.2cm, BC= 6cm, CD=5.2cm, DA=5cm and AC= 8 cm.

Given :

AB = 4.2 cm , BC = 6 cm , CD = 5.2 cm , DA = 5 cm , AC = 8 cm ,

Construction :

Step 1 : Draw segment AB of length 4.2 cm.

Step 2 : Taking A as centre draw an arc of radius 8 cm.

Step 3 : Taking B as centre draw an arc of radius 6 cm, which cuts the arc drawn in step 2. Point of intersection of two arcs is C.

Step 4 : Join AC and BC.

Step 5 : Taking A as centre draw an arc of radius 5 cm.

Step 6 : Taking C as centre draw an arc of radius 5.2 cm, which cuts the arc drawn in step 5. Point of intersection of two arcs is D.

Step 7 : Join AD and CD.

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