Q. 30

# Find the area of

Given the boundaries of the area O befound are,

• Curve is y2 = 2x +1

• Line x-y = 1

Consider the curve

y2 = 2x +1 This clearly shows, the curve is a parabola with vertex Consider the curve, y2 = 2x +1 and substitute the line x = y +1 in the curve

y2 = 2(y+1) +1

y2 = 2y +2 +1

y2 = 2y +3

y2 -2y -3 = 0 y = 3 (or) y = -1

substituting y in x-y = 1

x = 4 (or) x = 0

So , the parabola meets the line x-y =1 at 2 points, B (4,3) and C (0,-1) As per the given boundaries,

• The parabola y2 = 2x +1, with vertex at A(-0.5,0) and symmetric about the x-axis as y has even powers.

• Line x-y = 1

The boundaries of the region to be found are,

Point A, where the curve y2 = 2x +1 has the extreme end the vertex i.e. A (-0.5,0)

Point B, where the curve y2 = 2x +1 and the line x-y = 1 meet i.e. B (4,3)

Point C, where the curve y2 = 2x +1 and the line x-y = 1 meet i.e. B (0,-1) on the negative y

Point D, where the line x-y = 1 meets the x-axis i.e. D(1,0)

Consider the curve,

y2 = 2x +1

2x = y2 – 1 Consider the line x – y = 1

x = y +1

Area of the required region = Area of ABDC

Area of ABDC = Area above CDB – Area above CAB   [Using the formula ]   The Area of the required region Rate this question :

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