Answer :

The steps of the required construction are:

1) Draw a line segment BC=7cm. Using a protractor, draw ∠CBD=60°. Join and extend BD.

2) Taking B as the center and radius=12cm, draw an arc, intersecting extended BD at point P. Join PC.

3) Taking P as the center and radius greater than , draw arcs on each side of PC. Now, taking C as the center and same radius, draw arcs, intersecting the previous arcs at points Q and R. Join and extend QR. Extended QR intersects line segment DB at point A. Join AC.

4) ∆ABC is the required triangle.

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