Q. 24.6( 8 Votes )

<span lang="EN-GB

Answer :

The steps of the required construction are:

1) Draw a line segment BC=4.5cm. Using a protractor, draw CBD=45°. Join and extend BD.



2) Taking B as the center and radius=5.6cm, draw an arc, intersecting extended BD at point P. Join PC.



3) Taking P as the center and radius greater than , draw arcs on each side of PC. Now, taking C as the center and same radius, draw arcs, intersecting the previous arcs at points Q and R. Join and extend QR. Extended QR intersects line segment DB at point A. Join AC.



4) ∆ABC is the required triangle.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses