Answer :
We have,
f(x) = 
– x sinx
f ’(x) = 2x – sin x – x cos x
Now,
x 
(
)
⇒ 0
sin x 
1, 0
cos x 
1,
⇒ 2x–sin x –x cos x > 0
⇒ f ’(x) ≥ 0
Hence,f(x) is an increasing function on (
).
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