Answer :

Given that a student needs to choose 5 courses out of 9 courses. It is also told 2 courses are compulsory to the student.


It is similar to choosing 3 courses of remaining 7 courses since 2 courses are already chosen.


Let us assume the no. of ways of choosing to be N,


N = (no. of ways of choosing 3 courses out of remaining 7 courses)


N = 7C3


We know that ,


And also n! = (n)(n – 1)......2.1





N = 35


The no. of ways of choosing 5 courses is 35.


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