# Find the number of ways of selecting 9 balls from 6 red balls, 5 white balls, and 5 blue balls if each selection consists of 3 balls of each color.

Given that we need to select the 3 red, 3 white, and 3 blue balls out of 6 red, 5 white and 5 blue balls.

Let us assume the no. of ways of selection be N.

N = (no. of ways of selection of 3 red balls out of 6 red balls) × (no. of ways of selection of 3 white balls out of 5 white balls) × (no. of ways of selection of 3 blue balls out of 5 blue balls)

N = (6C3) × (5C3) × (5C3)

We know that ,

And also n! = (n)(n – 1)......2.1

N = 20 × 10 × 10

N = 2000

The no. of ways of selection is 2000.

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