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# In how many ways can a team of 3 boys and 3 girls be selected from 5 boys and 4 girls?

Answer :

Given that we need to select a team consisting of 3 boys and 3 girls out of 5 boys and 4 girls.

Let us assume the no. of ways of selection be N.

⇒ N = (Selecting 3 boys out of 5 boys) × (selecting 3 girls out of 4 girls)

⇒ N = (^{5}C_{3}) × (^{4}C_{3})

We know that ,

And also n! = (n)(n – 1)......2.1

⇒

⇒

⇒

⇒ N = (10) × (4)

⇒ N = 40

∴ The no. of ways of selecting 3 boys and 3 girls is 40.

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