Q. 215.0( 1 Vote )

# Find the number of (i) diagonals (ii) triangles formed in a decagon.

i. We know that the decagon has 10 vertices and each side and diagonal can be formed by joining two vertices of a hexagon,

We know that decagon has 10 sides,

Let us assume the no. of diagonals of the hexagon are N,

N = (no. of lines formed on joining any two vertices) – (no. of sides of the hexagon)

N = 10C2 – 10

We know that ,

And also n! = (n)(n – 1)......2.1   N = 45 – 10

N = 35

The total no. of diagonals formed is 35.

ii. Given that we need to find the no. of triangles that can be drawn in a decagon.

We know that 3 points are required to draw a triangle.

We know that decagon has 10 sides

Let us assume the no. of triangles formed be N1,

N1 = (total no. of triangles formed by all 10 points)

N1 = 10C3

We know that ,

And also n! = (n)(n – 1)......2.1   N1 = 120

The total no. of ways of different lines formed are 120.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos  Challenging Quiz on P&C | Test Yourself55 mins  Lecture on Combinations49 mins  Check Your progress Part 2| Interactive Quiz: Permutation & CombinationFREE Class  Understand Permutations like never before60 mins  Interactive Quiz on Division and distribution of objects17 mins  Combinations - BOX & GAP Method38 mins  Interactive Quiz on Combinations50 mins  Lets see how good you can manage numbers | P&C Quiz Challenge41 mins  Ladoo Bhikhari Concept46 mins  Indepth Understanding of Factorials56 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation view all courses 