# How many different boat parties of 8, consisting of 5 boys and 3 girls, can be made from 25 boys and 10 girls?

Given we need to find the different boat parties of 8, consisting of 5 boys and 3 girls.

The selections of girls and boys are to be made from 25 boys and 10 girls.

Let us assume the number of ways of choosing to be N.

N = (no. of ways of choosing 5 boys) × (No. of ways of choosing 3 girls)

N = (25C5) × (10C3)

We know that ,

And also n! = (n)(n – 1)(n – 2)…………2.1

N = (53130) × (120)

N = 6375600

The total no. of different boat parties are 6375600 ways.

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