Q. 20 D4.8( 5 Votes )

# Let r and n

Given that we need to prove nCr + 2nCr – 1 + nCr – 2 = n + 2Cr

Consider L.H.S,

We know that nCr + nCr + 1 = n + 1Cr + 1

nCr + 2nCr – 1 + nCr – 2 = (nCr + nCr – 1) + (nCr – 1 + nCr – 2)

nCr + 2nCr – 1 + nCr – 2 = n + 1Cr + n + 1Cr – 1

nCr + 2nCr – 1 + nCr – 2 = n + 2Cr

= R.H.S

L.H.S = R.H.S, thus proved.

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