# Find the angles m

In ΔBEC

BEC + ECB +CBC = 180° [Sum of angles of a triangle is 180°]

90° + 40° + CBC = 180°

CBC = 180°-130°

CBC =50°

B = D = 50° [Opposite angles of a parallelogram are equal]

A + B = 180° [Sum of adjacent angles of a triangle is 180°]

A + 50° = 180°

A = 180°-50°

A = 130°

In ΔDFC

DFC + FCD +CDF = 180° [Sum of angles of a triangle is 180°]

90° + FCD + 50° = 180°

FCD = 180°-140°

FCD =40°

A = C = 130° [Opposite angles of a parallelogram are equal]

C = FCE +BCE + FCD

DCF + 40° + 40° = 130°

DCF = 130° - 80°

DCF = 50°

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