Answer :

The centroid of a Δ whose vertices are (x1,y1), (x2,y2) and (x3,y3) is given by-



centroid of the given ΔABC ≡ [ (2-4 + 5)/3 , (2-4-8)/3 ]


≡ (1,-10/3)


Thus, the centroid of the given triangle ABC is (1,-10/3).


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