Q. 74.5( 13 Votes )

A(7, –3), B(5, 3)

Answer :


D = {(3 + 5)/2,(3–1)/2} = (4,1)


For triangle ABD


Area of triangle


= 1/2(x1(y2−y3) + x2(y3−y1) + x3(y1−y2))


= 1/2(7(3–1) + 5(1 + 3) + 4(–3–3))


= 1/2(14 + 20–24)


= 1/2(10)


= 5 sq unit


For triangle ACD


Area of triangle


= 1/2(x1(y2−y3) + x2(y3−y1) + x3(y1−y2))


= 1/2(7(–1–1) + 3(1 + 3) + 4(–3 + 1))


= 1/2(–14 + 12–8)


= 1/2(10)


= 5 sq unit


Hence area of triangle ABD and ACD is equal.


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