Answer :


For triangle ABC


Area of triangle


= 1/2(x1(y2−y3) + x2(y3−y1) + x3(y1−y2))


= 1/2(3(–5–0) + 9(0 + 1) + 14(–1 + 5))


= 1/2(–15 + 9 + 56)


= 1/2(50)


= 25


For triangle ACD


Area of triangle


= 1/2(x1(y2−y3) + x2(y3−y1) + x3(y1−y2))


= 1/2(3(0–19) + 14(19 + 1) + 9(–1–0))


= 1/2(–57 + 280–9)


= 1/2(214)


= 107


Area of ABCD = Area of ABC + Area of ACD


= 25 + 107


= 132 sq units


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