Answer :


We know that the diagonals of a parallelogram bisect each other


So the coordinates of the mid – point of the PR = Coordinates of the mid – point of the QS


{(2 + a)/2,(15 – 11)/2} = {(5 + 1)/2,(b + 1)/2}


2 + a = 6


a = 4


15 – 11 = b + 1


4 = b + 1


b = 3


Hence, a = 4, b = 3


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