Q. 12
If A + B + C = π, prove that
tan 2A + tan 2B + tan 2C = tan 2A tan 2B tan 2C
Answer :
= tan 2A + tan 2B + tan 2C
Since A + B + C = π
A + B = π – C
2A + 2B = 2π – 2C
Tan (2A+2B) = tan (2π – 2C)
Since tan (2π – C) = -tan C
Tan (2A + 2B) = -tan 2C
Now using formula,
Tan 2A + tan 2B = -tan 2C + tan 2C tan 2B tan 2A
Tan 2A + tan 2B + tan 2C = tan 2A tan 2B tan 2C
= R.H.S
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If A + B + C = π, prove that
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