Q. 74.7( 3 Votes )

# In Fig. 16.182, <

Given that,

OBD = 50o

Since,

AB and CD are the diameters of the circles and O is the centre of the circle

Therefore,

PBC = 90o (Angle in the semi-circle)

OBD + DBC = 90o

50o + DBC = 90o

DBC = 40o

By degree measure theorem,

AOC = 2 ABC

AOC = 2 * 40o

= 80o

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