Answer :
Given that,
∠BOC = 100o
By degree measure theorem,
∠AOC = 2 ∠APC
100o = 2 ∠APC
∠APC = 50o
Therefore,
∠APC + ∠ABC = 180o (Opposite angles of a cyclic quadrilateral)
50o + ∠ABC = 180o
∠ABC = 130o
Therefore,
∠ABC + ∠CBD = 180o (Linear pair)
130o + ∠CBD = 180o
∠CBD = 50o
Rate this question :
How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Tips to Solve RD Sharma Problems Faster23 mins
Smart Revision | Most Important Questions of Circles45 mins
RD Sharma | Extra Qs. of Cyclic Quadrilaterals31 mins
Let's Solve Good Questions on Circle41 mins
Some Imp Concepts Of Circles44 mins
NCERT | Imp Qs Discussion on Circles39 mins
Smart Revision | World of Circles44 mins
Smart Revision | Chords and Related Concepts42 mins
Concept of Cyclic Quadrilateral61 mins
NCERT | Quiz on Circles45 mins




















Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
view all courses
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation


RELATED QUESTIONS :
In Fig. 16.195, <
RD Sharma - Mathematics<span lang="EN-US
RS Aggarwal & V Aggarwal - Mathematics<span lang="EN-US
RS Aggarwal & V Aggarwal - MathematicsPQRS is a
RD Sharma - MathematicsABCD is a
RD Sharma - Mathematics<span lang="EN-US
RS Aggarwal & V Aggarwal - Mathematics<span lang="EN-US
RS Aggarwal & V Aggarwal - Mathematics<span lang="EN-US
RS Aggarwal & V Aggarwal - Mathematics<span lang="EN-US
RS Aggarwal & V Aggarwal - Mathematics<span lang="EN-US
RS Aggarwal & V Aggarwal - Mathematics